# Python uses while to find the integer sum within 100

Time：2022-5-6
##### catalogue
• 1. Sum of 1 to 100
• 2. Even sum from 1 to 100
• 3. Odd sum from 1 to 100

## 1. Sum of 1 to 100

Define 2 variables I and`sum`, the initial value is 1, and the value of I increases by 1 every time. After taking 100, the program ends,`sum`The value of is equal to itself plus the value of I. In this way, I is taken from 2 to 100 and added to sum every time.

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 1 2 3 4 5 6 7 8 9 10 `#!/usr/bin/env python` `#-*- coding:utf-8 -*-` `i``=``1` `sum``=``1` `while` `True``:` `    ``i``+``=``1` `    ``sum``=``sum``+``i` `    ``if` `i``=``=``100``:` `        ``break` `print``(``sum``)`

## 2. Even sum from 1 to 100

Method 1:The same as above, except that the initial value of I and sum is 0, and the value of I increases by 2 every time. After taking 100, the program ends.

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 1 2 3 4 5 6 7 8 9 10 `#!/usr/bin/env python` `#-*- coding:utf-8 -*-` `i``=``0` `sum``=``0` `while` `True``:` `    ``i``+``=``2` `    ``sum``=``sum``+``i` `    ``if` `i``=``=``100``:` `        ``break` `print``(``sum``)`

Method 2:By taking the remainder function%, let num% 2. If it is equal to 0, it will be an even number, sum = sum + num

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 1 2 3 4 5 6 7 8 9 10 11 12 `#!/usr/bin/env python` `# -*- coding:utf-8 -*-` `#Python learning exchange group: 778463939` `num``=``0` `sum``=``0` `while` `True``:` `    ``num``+``=``1` `    ``if` `num``%``2``=``=``0``:` `        ``sum``=``sum``+``num` `    ``if` `num``=``=``100``:` `        ``break` `print``(``"Task finished!The sum of even numbers from 1 to 100 is:  "``+``str``(``sum``))`

Tips:The equals sign is = =, which can no longer be written as num% 2 = 0.

## 3. Odd sum from 1 to 100

Method 1:The same as above, except that the initial value of I and sum is 1, and the value of I increases by 2 every time. Here, we need to pay special attention to that the program ends after the value of I reaches 99, otherwise the program will loop.

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 1 2 3 4 5 6 7 8 9 10 `#!/usr/bin/env python` `#-*- coding:utf-8 -*-` `i``=``int``(``1``)` `sum``=``int``(``1``)` `while` `True``:` `    ``i``+``=``2` `    ``sum``=``sum``+``i` `    ``if` `i``=``=``99``:` `        ``break` `print``(``sum``)`

Method 2:By taking the remainder function%, let num% 2. If it is equal to 1, it will be an odd number, sum = sum + num

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 1 2 3 4 5 6 7 8 9 10 11 `#!/usr/bin/env python` `# -*- coding:utf-8 -*-` `num``=``0` `sum``=``0` `while` `True``:` `    ``num``+``=``1` `    ``if` `num``%``2``=``=``1``:` `        ``sum``=``sum``+``num` `    ``if` `num``=``=``100``:` `        ``break` `print``(``"Task finished!The sum of odd numbers from 1 to 100 is:  "``+``str``(``sum``))`

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