PHP upload pictures to the database and display the example code

Time:2021-11-21

PHP uploads pictures to the database and displays them

1. Create data table


CREATE TABLE ccs_image (

 id int(4) unsigned NOT NULL auto_increment,

 description varchar(250) default NULL,

 bin_data longblob,

 filename varchar(50) default NULL,

 filesize varchar(50) default NULL,

 filetype varchar(50) default NULL,

 PRIMARY KEY (id)

)engine=myisam DEFAULT charset=utf8

2. Page upimage.html for uploading pictures to the server

<!doctype html>

<html>

<head>

  <meta charset="UTF-8">

  <meta name="viewport"

     content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0">

  <meta http-equiv="X-UA-Compatible" content="ie=edge">

  <style type="text/css">

    *{margin: 1%}

  </style>

  <title>Document</title>

</head>

<body>

<form method="post" action="upimage.php" enctype="multipart/form-data">

  Description:

  <input type="text" name="form_description" size="40">

  <input type="hidden" name="MAX_FILE_SIZE" value="1000000"> <br>

  Upload file to database:

  <input type="file" name="form_data" size="40"><br>

  <input type="submit" name="submit" value="submit">

</form>

</body>

</html>

3. PHP upimage.php for image upload

<?php

if (isset($_POST['submit'])) {

  $form_description = $_POST['form_description'];

  $form_data_name = $_FILES['form_data']['name'];

  $form_data_size = $_FILES['form_data']['size'];

  $form_data_type = $_FILES['form_data']['type'];

  $form_data = $_FILES['form_data']['tmp_name'];

   

  $dsn = 'mysql:dbname=test;host=localhost';

  $pdo = new PDO($dsn, 'root', 'root');

  $data = addslashes(fread(fopen($form_data, "r"), filesize($form_data)));

  //echo "mysqlPicture=".$data;

   

  $result = $pdo->query("INSERT INTO ccs_image (description,bin_data,filename,filesize,filetype)

         VALUES ('$form_description','$data','$form_data_name','$form_data_size','$form_data_type')");

  if ($result) {

    Echo "the picture has been stored in the database";

  } else {

    Echo "request failed, please try again";

Note: pictures are stored in the database in the form of binary blobs, like this

4. PHP getimage.php showing the picture

<?php

 

  $id =2;// $_ GET['id'];  For simplicity, the ID is written directly. Normally, it should be obtained through the ID filled in by the user

  $dsn ='mysql:dbname=test;host=localhost';

  $pdo = new PDO($dsn,'root','root');

  $query = "select bin_data,filetype from ccs_image where id=2";

  $result = $pdo->query($query);

  $result = $result->fetchAll(2);

//  var_dump($result);

  $data = $result[0]['bin_data'];

  $type = $result[0]['filetype'];

  Header( "Content-type: $type");

  echo $data;

5. Go to the browser to view the uploaded pictures to see if they can be displayed

The above is all the relevant knowledge points introduced this time. Thank you for your learning and support for developeppaer.