Find the first data string in the row

Copy codeThe code is as follows:

@echo off
:: find the record in the form of < input name = ID value = 1842 type = hidden >
:: the first digit string of
: by detecting the type of each character to get, but the efficiency is very low
:: code by jm 2006-10-16 [email protected]
set num=0
setlocal enabledelayedexpansion
for /f “delims=” %%i in (input.txt) do call :intercept “%%i”
echo value=%str_%
pause
goto :eof
:intercept
set str=%1
set str=%str:~2,-2%
if not “%str%”==”” echo. “%str:~0,1%”|findstr “[0-9]”>nul && (
set num=1&set str_=!str_!%str:~0,1%&&call :intercept ” !str:~1! “)||(
if %num% equ 0 call :intercept ” !str:~1! ”
)
goto :eof
No alternative scheme, does not rely on the character before and after the relationship, will get any value after value = very fast
It can handle more data, such as input type = hidden name = ID value = 465974855 < input type = hidden name = ID value = 1820988170 > < input type = hidden name = ID value = 1008964101 >
String of
@echo off
setlocal enabledelayedexpansion
FOR /f “delims=” %%i in (input.txt) do (
set “t=%%i”
set “t=!t:<= !”
set “t=!t:>= !”
set “t=!t:&= !”
set “t=!t:|= !”
call :sub !t !
)
pause
goto :eof
:sub
if “%1” == “” exit /b
if “%F%” == “1” echo %1 &set F=0
if “%1” == “value” set F=1
shift
goto sub